When 15-kg of some unknown at 180°C is added to 4-kg of water at 20°C the...
How much heat must be removed to completely freeze 15 kg of water initially at 95°F? For water : Cice = 2100 J kg.K Cwater = 4186 kg K Lf=3 J . 34 x 10° ke, L, = 2. 26 x 100 kg
How much ice is in the final state after 2 kg of ice at -30°C is added to a large quantity of water at 0°C? The final state is ice-water. (The temperature of the ice increases to 0°C and some of the water freezes.) J For water : Cice = 4186 J kg.K If = 3 = 2100 kg.K : Cwater L, = 2.26 x 106 .34 x 10% J kg 9 kg
A beaker with negligible mass contains 0.50 kg of water at a temperature of 80 °C. How many grams of ice at a temperature of -20 °C must be dropped in the water so that the final temperature of of the system is 30 °C? (Cice = 2100 J/ (kg °C) ), Cwater = 4190 J/ (kg °C) ), LF = 3.33 x 105 J/kg Could you also show how LF is used?
How much heat is required to convert solid ice with a mass of 850 g and at a temperature of -26.5 °C to liquid water at a temperature of 64.5 °C? (The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is: Lf = 334 kJ/kg.)
How much heat is required to convert solid ice with a mass of 585 g and at a temperature of -29.0 °C to liquid water at a temperature of 74.5 °C? (The specific heat of ice is cice = 2100 J/kgK, the specific heat of water is cwater = 4186.8 J/kgK, and the heat of fusion for water is: Lf = 334 kJ/kg.)
How much heat is required to convert solid ice with a mass of 525 g and at a temperature of-23.5 °C to liquid water at a temperature of 48.5 °C? (The specific heat of ice is cice = 2100 /kgK, the specific heat of water is cwater-4186.8 J/kgK, and the heat of fusion for water is: Lf 334 kJ/kg.) Submit Answer Tries 0/12
20 kg of steam at 383 K transfers Q = 1.5 × 106 J of its energy to the environment. What is the mass of water that condenses? (The latent heat of fusion is Lf = 3.3 × 105 (J/kg) and the latent heat of vaporization is Lv = 2.26 × 106 (J/kg). The specific heat of steam is csteam = 2010 (J/(kg ◦C) and cwater = 4186 (J/(kg ◦C).) A) 0.0 kg B) 0.5 kg C) 7.2 kg D)...
In the specific heat capacity experiment, the unknown object has a mass of 0.073 kg and was cooled to -9 C. Then, it was placed in a calorimeter (mcalorimeter = 0.11 kg) that contain water (mwarter = 0.23 kg) at a temperature of 26 C. After 5 minutes the temperature dropped to 22.4 C. Determine the specific heat capacity of the unknown object. (cwater = 4186 J/kg. C and ccalorimeter = 900 J/kg. C)
In the specific heat capacity experiment, the unknown object has a mass of 0.070 kg and was cooled to -3C. Then, it was placed in a calorimeter (mcalorimeter = 0.13 kg) that contain water (mwarter = 0.26 kg) at a temperature of 26 oC. After 5 minutes the temperature dropped to 24C. Determine the heat lost by the water. (cwater = 4186 J/kg. C and ccalorimeter = 900 J/kg. C)
The energy needed to convert 2 kg of ice at -10 °C to water at 10 °C will be { Constants Given: Specific Heat of Water = 4186 J/kg ºc, Specific Heat of Ice = 2100 J/kg ºc, and Latent Heat of Fusion = 3.33 x 105 J/kg. }