Question 4 10 pts A source moving through the water at 10.0 m/s generates water waves...

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Answer 1

Answer #1

Answer:

Given, actual frequency f = 5.0 Hz, speed of the source v_s = 10.0 m/s and speed of the wave v = 20.0 m/s and speed of the observer v₀ = 0 m/s

(a) Wavelength of the produced wave before the observation is $\lambda$ = v/f = (20.0 m/s) / (5.0 Hz) = 4.0 m

First we will calculate part (c) and then go for part (b) for easy calculation.

(c) According to the Doppler's effect, the observed frequency f ' = [ (v + v₀) / (v - v_s) ] f

Thus, f ' = [ (20.0 m/s + 0 m/s) / (20.0 m/s - 10.0 m/s) ] (5.0 Hz) = 10.0 Hz

(b) The wavelength of the observed wave is $\lambda$ ' = v / f ^' = (20.0 m/s) / (10.0 Hz) = 2.0 m

(d) If the observer is moving with the speed 10 m/s and the source is at rest.

That means, v₀ = 10 m/s and v_s = 0 m/s

Then, the measured frequency is f ' = [ (v + v₀) / (v - v_s) ] f

f ' = [ (20.0 m/s + 10 m/s) / (20.0 m/s - 0.0 m/s) ] (5.0 Hz) = 7.5 Hz

Answer 2

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