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PLEASE ANSWER 5-9 USING THE GIVEN TABLE AND THE ABOVE QUESTION

5-8. Three refineries with daily capacities of 6, 5, and 8 million gallons, respectively, supply three distribution areas wit

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Answer #1

5-8.

(a)

Transportation cost from refinery to distribution area = Distance * (0.10 / 1000)*10^6 per million gallons

= 100 * distance per million gallons

Associated transportation model is following:

Transportation cost per million gallons Distribution area 1 Distribution area 2 Distribution area 3 Capacity (million gallons)
Refinery 1 12,000 18,000 100000* 6
Refinery 2 30,000 10,000 8,000 5
Refinery 3 20,000 25,000 12,000 8
Demand (million gallons) 4 8 7

* Hypothetically high cost (100000) is assigned to cell 13 to prohibit allocation to this cell , as Refinery 1 is not connected to distribution area 3

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(b)

Set up spreadsheet model as follows:

C D E F 2 3 18,000 1,00,000 10,000 8,000 25,000 12,000 8 7 Capacity 6 5 8 A B 1 Transportation Table 2 1 3 Refinery 1 12,000

EXCEL FORMULA:

A B D E 1 Transportation Table 2 1 Capacity 6 2 18000 10000 25000 3 100000 8000 12000 5 8 3 Refinery 1 12000 4 Refinery2 3000

Set up Solver Parameters as follows:

Solver Parameters X Set Objective: $B$15 1 To: Max Min O 0 Value of: By Changing Variable Cells: $B$10:$D$12 1 Subject to the

Click Solve .

After that, values appear automatically in yellow colored cells

с D E F 2 3 Capacity 6 5 18000 10000 25000 8 100000 8000 12000 7 8 А B 1 Transportation Table 2 1 3 Refinery 1 12000 4 Refine

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5-9.

(a)

Setup Transportation model as follows:

B с D E F 1 2 18000 10000 25000 50000 8 3 100000 8000 12000 50000 7 Capacity 6 5 6 2 A 1 Transportation Table 2 3 Refinery 1

* Hypothetically high cost (100000) has been assigned to cell 41 to prohibit allocation to this cell , because no shortage is allowed for area 1, as it must receive all its demand

EXCEL FORMULA:

с D E 2 Capacity 6 5 2 18000 10000 25000 =0.05*10^6 8 3 100000 8000 12000 =0.05*10^6 7 6 2 1 Transportation Table 1 3 Refiner

Solver Parameters:

Solver Parameters Х Set Objective: $B$17 To: Max Min Value of: 0 By Changing Variable Cells: $B$11:$D$14 Subject to the Const

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(b)

Click Solve to generate the solution:

A B с D E F G H K L M N O 3 Capacity 6 Solver Results 1 Transportation Table 2 1 3 Refinery 1 12000 4 Refinery 2 30000 5 Refi

Click OK

.

Total cost = $ 304,000

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