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1. V In a slider crank mechanism, link AC is massless and it is Limped Mass Model rotating at a constant angular velocity of 300 rpm. A point weight of 12 lb is attached at point C. Using the lumped mass 25 lb mg method, calculate the magnitudes of the resultant shaking B forces in x and y directions for the instant shown. 208 m. = m -0.414; 1.+1 322112) 20 + ms 12 (2) -0.207; =m -0.218 7+1 322112 32.2 3 m = m. + m - 0.248 0.414 = 0.166 20 lb 25 m, = m+m, = 0.207 + = 0.983 32.2 ärzrocos @& +' cos 2011 300(2x) 3 300 rpm 60 Shaking force from the pure rotation of mass at A 30° 30 Fs = m ,røʻ=0,166 300(2x) = 40.96 lb / 02 = Es, - 40.96 (cos 30i – sin 30j)ib 12 lb Shaking force from the pure translation of mass at B с Fs, = m;* m; f = 0.983(244.53)= 240.37 16 = Es --240.371 lb = F. = |(40.96 cos 30–240.37) = -204.9 16 and |15|-|(40.96 sin 30)-20.48 76 х - Cybooke :) cut-30 300 rpm o פון 22 3 دریا 2" TG2