Question

Two pizzas with 8 inch and 16 inch diameters are each cut into 6 equal pieces. How does the area of each piece of the smaller pizza compare to the area of each piece of the larger pizza? [G-SRT.5] O 1/2 the size O 1/4 the size O 1/6 the size O 1/3 the size

Answer 1

Area of pizza 1 = $\small \pi \times (4)^{2}=16\pi\textup{ sq.inches}$

Area of pizza 2 = $\small \pi \times (8)^{2}=64\pi\textup{ sq.inches}$

Each one of them is cut into 6 equal pieces.

Area of each piece of pizza 1 = $\small \frac{16\pi}{6}\textup{ sq.inches}$

Area of each piece of pizza 2 = $\small \frac{64\pi}{6}\textup{ sq.inches}$

$\small \frac{\textup{Area of each piece of pizza 1}}{\textup{Area of each piece of pizza 2}}=\frac{16\pi /6}{64\pi /6}=\frac{1}{4}$

Answer: option (b): (1/4)th the size.