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Problem 1. Find the Fourier series expansion of a half-wave rectified sine wave depicted below. AS(0) Answer: f(t) = 1+sin at

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Problem- from the Consider figure question. the f10 T 1 t define the function from the above figure. S TU sin. f(t)- (it). Ocfunction becomas ft? M 8 grunt ao t 2 n=1 (on con sin (en bn Sin f(t)= aot E nal है an 6s (rent) + bn Sin (rent) ] O where docă [-65T6 + 650 PL do=1 T do / + 2 Constant an find the value of from expression. Where An = dit S f (t) Gs (art) at nti an =an - & [ Corinting Gs (ntila nt1 an- n+? - (no) Gs (ntir- n24 Cos (n+1.l.re - Where nel 127 find the valce of Gnstow 01 ay alfrom the find the valice of bn expression bn 3 f(t) Sin (not) olf alt L Wher nz2 bn - ald rt sin (tt) Sin (nat) dt bn 2 bn =find The value of a constant bi bia So to To Sin (Tt) sin(red) dt bi a al sin2 let) alt b = n Gs Cent) 2 Sin (art) 1 . bis TOf (tia It E 6s (n+1) rot net Gs (not) n=2 + TU 2 sin ntut expending above eguation f(t) = lt i sin inato 2 Gs (2008) 2 Wlo 2

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