Question

A wave with an amplitude of 2.5 cm, a frequency of 12 Hz and a wavelength of 45 cm travels down a string with a linear density of 0.00245 kg/m. What is the maximum speed and maximum acceleration of a point on the string as the wave passes?

Answer 1

Maximum speed, $v_{max} = \omega A = 2 \pi f A = 2 \pi *12 *0.025 =1.88 m/s$ maximum acceleration,$a_{max} = \omega^2 A = (2 \pi f)^2 A = (2 \pi *12) ^2*0.025 =142. 12m/s^2$