Question

An electron with a speed of 1.7 x 107 m/s moves horizontally into a region where a constant vertical force of 5.7 * 10-16 N acts on it. The mass of the electron is 9.1110-31 kg. Determine the vertical distance the electron is deflected during the time it has moved 31 mm horizontally Number Units

Answer 1

Time taken to travel the horizontal distance of 31 mm, t = x / v
Where x is the horizontal distance and v is the horizontal velocity of the electron.
t = (31 * 10^-3) / (1.7 * 10⁷)
= 1.82 * 10^-9 s
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Initial vertical velocity, u = 0
Vertical acceleration, a = F / m
Where F is the force and m is the mass.
a = (5.7 * 10^-16) / (9.11 * 10^-31)
= 6.26 * 10¹⁴ m/s
Time taken, t = 1.82 * 10^-9 s

Using the formula, y = u * t + 1/2 * a * t²,
y = 0 + 0.5 * (6.26 * 10¹⁴) * (1.82 * 10^-9)²
= 1.04 * 10^-3 m