Question

A steel column is made by welding two 10 in x 0.8 in plates to a W8 x 48 shape as shown in the figure 1. Knowing that the effective length of the column is 24 ft, determine the allowable centric load using the AISC code. Use Sy = 36 ksi and E = 29 x 10⁶ psi

W8 x 48 properties: A (in2) d(in) bf (in) tr(in) tw (in) Ix (in) x(in) ly (in“) ry(in) 14.1 8.5 8.11 0.685 0.4 184 3.61 60.9 2.08 Y 5 in. t d X 5 in. Y -by- Figure 1 - column cross section

Answer 1

Complete solution is given below.

W 8X 48 Ag = Holin² Iy = 60.9 inh be 8.11 in Ix 184 inh 1. property of britt up section logol + Caex rox0.8) 30.1 in ² | Ag Ix = 184 + Qx0.8x103 12 (e 8x103) in ly = 60.9 + {ex 30X0.5 *)+ (2x10x8 (840,47 Ix - 317.33 in 4 60.9 + 317.55 0.853 + Iy 379.3 int . Emin Imin A 311.33 30.1 3.247 in Klu 24 x 12 3.247 11 88.7

From AISC Table 4-22 For Fy = 36 ksi and fel = 8817 21.46 ksi $for For 2 = 14.23 ksi 2 Ultimate istrength $pm $Fen x Ag 21.46 X 30.1 <ppn = 645.95 kips) Allowable load pa Feu 14.23 X30.1 Pa = 428. 32 kips