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Which of the following ions CANNOT form both a high spin and low spin octahedral complex...
Which one of the following octahedral complex ions is diamagnetic? Note: NH3 is a strong-field ligand. (a) [Fe(NH3)6] 3+ (b) [Fe(NH3)6] 2+ (c) [Cr(NH3)6] 3+ (d) [Cr(NH3)6] 2+ (e) [Co(NH3)6] 2+
Which of the following species is diamagnetic? an isolated, gas-phase Co2+ ion a high-spin octahedral Ru2+ complex a low-spin octahedral Os2+ complex an isolated, gas-phase Ni2+ ion
All of the following complexes are either octahedral or tetrahedral. Determine if the complex is diamagnetic or paramagnetic, if the complex is high spin or low spin, and ii) the number of unpaired electrons. Unpaired Electrons Spin low Magnetism Complex [Fe(CN)6]* [Co(NH3)4]3 13+ 14- 4+ [Ru(CO)6] All of the following complexes are either octahedral or tetrahedral. Determine if the complex is diamagnetic or paramagnetic, if the complex is high spin or low spin, and ii) the number of unpaired electrons....
3) The d orbital electron configuration of octahedral complexes can either be described as high- spin with the maximum possible number of unpaired d-electrons, or low-spin containing one or more paired d-electrons. [Fe(H20)62 is a high-spin octahedral complex. What is its spin- state (S-?)? Draw a d-orbital splitting diagram for this complex and fill it with the appropriate number of electrons. Where does the final electron go in this diagram? If you were to oxidize this molecule do you think...
Question 2 5 pts The octahedral complex hexacyanoferrate(III) ion, [Fe(CN).l, is a low-spin complex. How many unpaired electrons does the complex have? OS OO 03 04 O1
1- Draw the molecular orbital diagram of transition metal ion in high-spin Mn(H2O)4(OH)2 complex, also determine the number of unpaired electron. 2- Draw the molecular orbital diagram of transition metal ion in low-spin [Cr(en)2(NH3)2].Cl2 complex, also determine the number of unpaired electron. 3- Draw the molecular orbital diagram of transition metal ion in high-spin K.[Mn(CO)3(OH)3] complex, also determine the number of unpaired electron.
5) Draw d orbital splitting of an octahedral complex. Calculate CFSE for a high spin Fe(II) complex in an octahedral geometry. Calculate spin only magnetic moment for the complex too. 6
1.- Define what are complex ions 2.- Using NiCl as a reactant look in a book or in the web for a reaction to form a complex ion, indicate which is the Lewis acid and which is the Lewis base. An example of your answer is this: Ag (aq) + 2NH, (aq) - Ag(NH),(aq) Lewis acid Lewis base 3.- Using the rules of nomenclature name the complex you have proposed in question 2 4.- Indicate the coordination number and geometry...
Which orbital diagram represents the electron configuration of high-spin octahedral complex [Cr(NH3)6]2+? Select the correct answer below: d₂2 dx?_v2 sp p гр d₂2 dx² - y2 ep "p 2ър прес d₂2 dx² - y2 ep "p 2ър də də - у dxy dyz dyz
In the complex ion [ML6]n+, Mn+ has five d electrons and L is a strong field ligand. According to crystal field theory, the magnetic properties of the complex ion correspond to how many unpaired electrons? A. 0 B. 1 C. 2 D. 3 E. 5 Which one of these complex ions would absorb light with the shortest wavelength? A. [Co(H2O)6]2+ B. [Co(NH3)6]2+ C. [CoF6]4– D. [Co(CN)6]4– E. [Co(en)6]2+ The ion [Co(NH3)6]2+ is octahedral and high spin. This complex is (4pts)...