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1. 25.00 mL of a of 0.100M solution of formic acid (HCO:H, pK, - 3.74) is...
1. 25.00 mL of a of 0.100M solution of formic acid (HCO,H, PK: - 3.74) is titrated with 0.125 Min NaOH. What is the pH at each of the following? (5 points each) a. After the addition of 15.00mL of NaOH solution 6. After the addition of 20.00 mL of NaOH solution C. After the addition of 25.00 mL of NaOH solution d. At what volume of added NaOH will pH -pK
1. 25.00 mL of a of 0.100M solution of formic acid (HCO,H, pK, = 3.74) is titrated with 0.125 Min NaOH. What is the pH at each of the following? (5 points each) a. After the addition of 15.00mL of NaOH solution. b. After the addition of 20.00 mL of NaOH solution c. After the addition of 25.00 mL of NaOH solution. d. At what volume of added NaOH will pH =pK,
1. 25.00 mL of a of 0.100M solution of formic acid (HCO.H, pk. = 3.74) is titrated with 0.125 Min NaOH. What is the pll at each of the following? (5 points each) a. After the addition of 15.00mL of NaOH solution b. After the addition of 20.00 mL of NaOH solution c. After the addition of 25.00 ml. of NaOH solution d. At what volume of added NaOH will pll apk.
1. 25.00 mL of a of 0.100M solution of formic acid (HCO,H, PK, = 3.74) is titrated with 0.125 Min NaOH. What is the pH at each of the following? (5 points each) a. After the addition of 15.00mL of NaOH solution. b. After the addition of 20.00 mL of NaOH solution c. After the addition of 25.00 mL of NaOH solution. d. At what volume of added NaOH will pH =pK. 2. A solution is made as follows: 2.735g...
3. In the lab you are going to titrate a weak acid solution (25.00 mL of 0.100 M HCHO2, formic acid) with a strong base (0.100 M NaOH). Carry out the following calculations to determine the pH for four key points throughout the titration. Part a. Calculate the volume of 0.100 M NaOH required to reach the equivalence point for the titration. Ans. 25.00 mL Part b. Calculate the initial pH of 0.100 M HCHO2 (before adding any NaOH). Ans....
50.00 mL of 0.100M of a weak acid (Ka=1.3x10-5) is titrated with 0.100M NaOH. a. Compute the volume of NaOH required to reach the equivalence point. b. Calculate the pH of the original solution before any NaOH has been added. c. After 30.00 mL of NaOH has been added, what is the pH of the solution? d. What is the pH at the equivalence point? e. Write a brief explanation as to why it is...
An analytical chemist is titrating 204.4 ml of a 1.200 M solution of formic acid (H.CO) with a 0.5700 M solution of KOH. The pk of formic acid is 3.74. Calculate the pH of the acid solution after the chemist has added 126.2 ml of the KOH solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added. Round your answer to 2 decimal...
A 50.0 mL sample of 0.25 M formic acid (HCOOH) aqueous solution is titrated with 0.125 M NaOH solution. Ka of HCOOH = 1.7 x 10−4. a. Calculate the pH of the solution after 50 mL of NaOH solution has been added. b. How many mL of 0.125 M NaOH need to be added to the sample to reach the equivalence point? What is the pH at the equivalence point?
An analytical chemist is titrating 161.8 ml of a 1.100 M solution of formic acid (H.CO) with a 1.100 M solution of KOH. The pk of formic acid is 3.74 Calculate the pH of the acid solution after the chemist has added 176.4 ml of the KOH solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added. Round your answer to 2 decimal...
8. An analytical chemist is titrating 79.9 mL of a 0.7300 M solution of formic acid (HCOOH) with a 0.6000 M solution of KOH. The pk, of formic acid is 3.74 Calculate the pH of the acid solution after the chemist has added 19.5 ml of the KOH solution to it. Note for advanced students you may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added. Round you answer to 2...