Question

! Required information Consider the beam and loading shown where Pis 145 kN and E= 200 109 Pa. P SOKN.m SO KN.m B А с I W410 X 46.1 -2.5 m 2.5 m Determine the slope at end A. (Round the final answer to three decimal places.) The slope at end A is x 107 rad $

Answer 1

P = 145 KN 80kN-m C 2.5m 2.5m SOKN-m moment of Incalta foor section W410X 461 E 200 109 Pa - 200*10? No? Ixx = 156x106mm We will use conjengate beam mothed tullee to calculate required sloke at a aclording to Conjugele berom method, slope at Shear force at that any point in seal beam point in conjugate beam. Dxcuring Conjugate beaun, El dig Benling moment at it, MA=- 8 OKN-m Mogging at B, NlB = '18 Ok Now

at e Me = -80+ 145x5 4 101.25 KN." Mc sogging m EI dig A Conjugate be amo 101.25 EI A B EL EI 2.5m EL 2.5m Calculating Shear force, Ro' the' - 20x5 + $5(101.75180) RA the 53.125 EI EI EI due to symmetry in looding and structure, ho's Roc 53.125 २६ =) / RA RA = 26.5625 EI

According to Conjugate bean method. da = VÁ VA= Rn OA 26.5625 EI 26.5625 X10 Nr min 200.1103 N/mu? x 156 xlo mnou 85.136 x 105 xod. 08 OA = 0.8513x 103 rol