Question

A 2.00kg block initially at rest, is released from point A, as shown. The curved portion of the track is frictionless. The horizontal track, including the portion under the spring, has a kinetic coefficient of friction = 0.1. (a) What is the maximum compression if the spring? {take k=30N/m} (b) where does the block ultimately comes to rest?

4.A 2.00kg block initially at rest, is released from point A, as shown. The curved portion of the track is frictionless. The horizontal track, including the portion under the spring, has a kinetic coefficient of friction Hv = 0.1. (a) What is the maximum compression of the spring? (Take k=30N/m) (b)Where does the block ultimately comes to rest? (6-points) A h=1.5m d. 10m

Answer 1

The solution is given below.

4. potential energy mgh an = 2.00x 9.8x15 2.00kg go accelention due to groowing = 9.8 m/ 29.4 J ha Tom frictional fonce a My mg =or1 x 2.00x 9.8 work done 1.96 N compression of spring an by frictional force = 1.96 (10 tn) J potential energy stored in the spring star = 12x. 30422 = 15am of energy from conservation 15 x² + 1.96 (10ta) = 29.4 or, 1507 + 1906 + 1.962 = 2914 150 +1.262 -9.80 1-26 +5 (1.969*+ 4X1549.8 2f15 -1.96 e 24. 24 30 or ar 0.742 m Maximum compression Answer: 0.742 ror = 0.742 m The block comes to rest after moving (104 0.792) m horizonal surface 101742 m on the Answer: 10.742 m

Thank you.