As we know that the Laplace transform of
So,
Find the inverse Laplace transform of the given function: F(S) = 3! (s – 2)
3. Find the inverse Laplace transform of F(s)-
3. Find the inverse Laplace transform of F(s)-
Use the convolution theorem to find the inverse Laplace transform of the given function. 2 s(s? +1) 2 3 (s2 +1)
3 (1 point) Find the inverse Laplace transform f(t) = --! {F(s)} of the function F(s) = - 25 32 +25 $2 + 16 f(t) = -1 e='{-6816+,725)} = help (formulas)
(1 point) Find the inverse Laplace transform f(t) = 2" (F(s)} of the function F(s) = 2s 8²-1 (t) = -1 ^{}--G-- help (formulas)
Find the inverse Laplace transform of each function: 3 5. F(s) = 52-85+23
(1 point) Find the inverse Laplace transform f(t) = C-' {F(s)} of the function F(s) = 2s - 3 32 + 16 560) = c { 2s - 3 32 + 16 = 2cos(4t)-2 sin(4) help (formulas)
(1 point) Find the inverse Laplace transform f(t) = L-i {F(s)) of the function F(s) = 52-9 help (formulas) s+3 s-3
(1 point) Find the inverse Laplace transform f(t) = C-' (F(3)) of the function F(s) = 45 52 - 16 f(t) = -1 { 4s s2 - 16 } help (formulas) (6+4+2}- Preview My Answers Submit Answers
Chapter 6, Section 6.2, Question 04 Find the inverse Laplace transform --1{F(s)} of the given function. 6s+36 FS) $2+12s+100 Your answer should be a function of t. Enclose arguments of functions in parentheses. For example, sin (22). -1{F (3)} = QC
Find the inverse Laplace transform, f(t) of the 10 3 10 function F(s) + + s > 0 S 52 s + 10 f(t) = Preview t > 0 Submit License Question 2. Points possible: 2 Unlimited attempts. Message instructor about this question