Question

Mechanics of Materials. Need Help

(b) The A-36 solid steel shaft is 3.5 m long and has a diameter of 60 mm. The shaft is used to transmit a torque of T-524 Nm from the engine to the generator. Determine the angle of twist () of the shaft. The shear modulus of elasticity (G) of the shaft material is 75 GPa.

Answer 1

Title - Torsion Formula

Solution Given: Length, L = 3.5 m = 3.5 x 10²mm Diameter, D = 60 mm Torque, I = 524 N-m 524 X10 N-mm Shear modulus, G = 75 Gla=75x10²MPa To find Angle of twist (0) By Torsion formula, 2 T GO L J R where, T = Torque J = Polar Moment of Inertia ? = shear stress R = shaft Radius G = shear Modules Angle of twist L Length of shaft Т. G.0 L

: substituting values in above Equation to find angle of twist, o 524 x 109 75 X103 x 3 3.5 x 10 32 XD 524 X 103 75 x 109 x 0 11 3 3.5 X 10 ㅠ 32 x (60)4 ♡ 524 X 103 x 3.5 x 103 TT x (60)4 x 75 X 100 32 0.0192° = 3.3543 X104 radians o

Summary - Here the torsion formula is used to find the angle of twist of the shaft. The torque, polar moment of inertia, shear modulus and the length of shaft are the required data which is given in the question.