SSTr = 3*(2 - 2.583)^2 + 4*(2.5 - 2.583)^2 + 5*(3 - 2.583)^2 = 1.92
MSTr = 1.92/8 = 0.2344
Please give me a thumbs-up if this helps you out. Thank you!
= 3.0. The sample standard deviations were Samples were drawn from three populations. The sample sizes...
Samples were drawn from five populations. The sample sizes were n,=4, n=7, n3 = 4, n=5, ng=5. The sample means were x, = 49.75, 72 = 60.1429, 73 = 55.75, #4 = 64.2, X5= 48.8. The sample standard deviations were s = 4.5, 8z = 7.221, 8-6.8981, 54 = 4.6583, 85 - 4.5497. The grand mean was - 56.32. Part: 0/5 Part 1 of 5 (a) Compute the sums of squares ssir and sse. Round the answers to at least...
Independent random samples were selected from two quantitative populations, with sample sizes, means, and standard deviations given below. n1 = n2 = 60 x1 = 125.3 x2 = 123.4 s1 = 5.7 s2 = 6.1 a) Construct a 95% confidence interval for the difference in the population means (μ1 − μ2). (Round your answers to two decimal places.) to b) Find a point estimate for the difference in the population means. c) Calculate the margin of error. (Round your answer...
Independent random samples were selected from two quantitative populations, with sample sizes, means, and standard deviations given below. n1= 55, n2= 65, xbar1= 35.5, xbar2= 31.4, s1= 5.7, s2= 3.3 1.) Construct a 95% confidence interval for the difference in the population means (mu1- mu2). (Round your answers to two decimal places) 2.) Find a point estimate for the fifference in the population means. 3.) Calculate a margin of error. (Round your answer to two decimal places)
Independent random samples were selected from two quantitative populations, with sample sizes, means, and standard deviations given below. n = n2 = 90, x1 = 125.3, %2 = 123.8, s, = 5.7, s, = 6.9 Construct a 95% confidence interval for the difference in the population means ( M M ) (Round your answers to two decimal places.) Find a point estimate for the difference in the population means, Calculate the margin of error. (Round your answer to two decimal...
Two samples are taken with the following sample means, sizes, and standard deviations¯x1x¯1 = 33 ¯x2x¯2 = 26n1n1 = 55 n2n2 = 52s1s1 = 3 s2s2 = 4Find a 97% confidence interval, round answers to the nearest hundredth.___ < μ1−μ2μ1-μ2 < ___
Two samples are taken with the following sample means, sizes, and standard deviations 21 = 24 m2 = 31 ni = 60 n2 = 65 $1 = 5 82 = 3 Estimate the difference in population means using a 89% confidence level. Use a calculator, and do NOT pool the sample variances. Round answers to the nearest hundredth. <Hi - 42
Two samples are taken with the following sample means, sizes, and standard deviations 21 = 24 T2 = 31 ni = 60 n2 = 65 $1 = 5 82 = 3 Estimate the difference in population means using a 89% confidence level. Use a calculator, and do NOT pool the sample variances. Round answers to the nearest hundredth. <Mi - 42
Two samples are taken with the following sample means, sizes, and standard deviations ¯x1 = 25 ¯x2 = 23 n1 = 54 n2 = 73 s1 = 5 s2 = 3 Estimate the difference in population means using a 88% confidence level. Use a calculator, and do NOT pool the sample variances. Round answers to the nearest hundredth.
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1= 37 n2=44 x-bar1= 58.6 x-bar2= 73.8 s1=5.4 s2=10.6 Find a 97% confidence interval for the difference μ1−μ2μ1−μ2 of the means, assuming equal population variances.
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1=51, n2=46, x¯1=57.8, x¯2=75.3, s1=5.2 s2=11 Find a 94.5% confidence interval for the difference μ1−μ2μ1−μ2 of the means, assuming equal population variances. Confidence Interval =