Question

Find the magnitude of the linear momentum for the following cases. (Enter your answers in kg: m/s.) (a) a neutron with mass 1.67 x 10-27 kg, moving with a speed of 5.00 x 10 m/s 7.51x10^-2 kg-m/s (b) a 16.0-9 bullet moving with a speed of 300 m/s 4.8 kg. m/s (c) a 77.5-kg runner running with a speed of 10.0 m/s 987.5 x Remember that momentum is mass times velocity, kg. m/s (d) the Earth (mass 5.98 x 1024 kg) moving with an orbital speed equal to 2.98 x 104 m/s. 1.78x10^29 kg. m/s

Answer 1

-27 (a) mass of neutron, m= 1.67x 10-27 speed, v=5.00 x 106 mis momentum, Pamo = (1.67 x 10-9 x 5x106)ug.mls Pn ²8.35810 -21 kg. nls Ans (b) mass of buller, m = 16.00 : 0.016 kg We Sportin's 300 mis momentum, Poz mv (0.016 ug x 300 m/s) Po = 408 kg.mls to Aus (% mass of runner, m= 77.5 kg speed, uz 10.0 m/s momentum , Pomemv = (77.5 kg) x 10.0 mls Pp = 775 kg. mis tans kg (d) mass of Earth, m=5.98 10 24 speed, v=2.988 104 mis momentum, pe = mv = (5.98x102437) x(2.98x10m/s) Pe = 1078 X 1029 kg. mis Aus