(a) x = 3.5
s = 0.669
n = 6
df = 6 - 1 = 5
The t-critical value for df = 5 and from the t-table is 2.015.
The 90% confidence interval will be:
= x ± t*(s/√n)
= 3.5 ± 2.015*(0.669/√6)
= (2.9494, 4.0506)
(b) E = 0.20
z = 1.96
s = σ = 0.669
n = (1.96*0.669/0.20)^2 = 44
(c) E = 0.30
z = 1.96
s = σ = 0.669
n = (1.96*0.669/0.30)^2 = 20
Can you the answer with formula plz and I can not find Z0.05 in the table...
5. Normally the leaves of the Mimosa pudica are horizontal. However, if one of them is touched lightly, the leaflets will fold. It is reported that y, the true mean time from touch to complete closure is 3.0s. An experiment is run to test this value. A random sample of size observations on the elapsed time (seconds) from touch to complete closure yields the following data: 3.2, 4.4, 3.5, 2.9, 4.2, 2.8. Assume the population distribution of elapsed times is...