Question

PLEASE SHOW WORK!!!!!!!

1) A bicycle wheel with an 16 inch diameter rotates 1500. What distance has the bicycle traveled? 2) Find the exact values of the other five trig functions when sec = 5. 3) An airplane leaves the runway climbing at 210 with a speed of 275 feet per second. Find the altitude of the plane after 1 minute. 4) Find two values of 0 (0< < 27 ) that satisfy cos 0 = 0.9833. (Round your answers to 4 decimal places.) 5) Fill in the blanks with all possible answers. a. cot a > 0 and sin @ < 0 in the quadrant(s). b. sin (-2) = c. If -20 s 21 , then sec = -1 when =

Answer 1

plane is 250 Distance = 20.94 inch After 3 hours, Oistence between 662.63 mi Diameter 26 inch, Radius=sinch Revolution For 1 Revolution, wheel Revolutes 360 so; For 150 wheel Rotutes about 150 0.4167 360. (Revolution) Distance travelled by bicycle = Revolution X circumference of wheel of bicycle Wheel = 0.4267 x 2T (Radius) = 0.4167 x 2x TT X 8 Travelled

Seco= 5 1 1 so, cosco 0.2 seco & Sino = √2-cos²o Simo 0,9798 tano = sino coso = 0.9798 0,2 tamo = 4.8990 & Coto 1 tano Coto O. 2042 & coseco sino Coseco=1.02

B 16500 feet Plane Altitude 221° Here, Plane velocity = 275 second In a minute, plane travels of 16500 feet so distance A ABC, Now, IM Apply sine Rolle, sin 2 go Singo BC 165oo BC 5913.07 Altitude of plane after a minute 5913.07 feet, is

Coso = 0.9833 o e cos' (0.9833) 0.1830, 6.1002 - (5.) (a) coto >0 & sino co in the 390 quadeant (b.) sin(-o) = -Sinco (C.) If -2T so<2T), then seco=1 when ☺ = -TI, TT (d) The Reference angle tos 325° is 35 Co? 325 is in 4th quadrant th q For 4th guadrant Reference angle- = 360 - '09

(e) Two Coteaminal angles for 3T) are 11.7 q -5T 4 4 3T + 2T Positive angle ☺ q 3T - 2 T = 2T = Negative Negative angie म
BY THIS WAY, ANSWER OF GIVEN PROBLEM.