We are testing here whether the population mean is more than 2.85. The test statistic here is computed as:
For n - 1 = 8 degrees of freedom, and 0.01 level of significance, we have from t distribution tables here:
P( t8 < 2.896 ) = 0.99
Therefore P( t8 > 2.896) = 1 - 0.99 = 0.01
Therefore 2.896 is the required critical value here.
As the test statistic value here is 1.56 < 2.896, therefore it lies in the non rejection region here. Therefore we cannot reject the null hypothesis here. We have insufficient evidence that the mean is more than 2.85 here.
Preliminary data analyses indicate that it is reasonable to use as to carry out the specified...
are these two questions correct? Preliminary data analyses indicate that it is reasonable to use a test to carry out the specified hypothesis test. Perform the best using the critical value approach. Use a significance level of 0.01 to test the claim that > 265. The sample data consists of cows for which 312 and 300 For the toolbar, press ALT+F10 ( Por ALTEN F10/Mac) TT TT Paragraph Arial 312001 3. E. T. %DOQ TT. of hups -1.56 critical value...
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40 pts Preliminary data analyses indicate that it is reasonable to consider the assumptions for one-way ANOVA satisfied. Perform the required hypothesis test using the critical-value approach. At the 0.01 significance level, do the data provide sufficient evidence to support the claim that a difference exists between the population means of the three different brands? The sample data are given below. 47 Brand A Brand B Brand C 44 30 28 32 27 44 34 31 40 36 38 36...
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