Question

7. [-/10 Points DETAILS LARCALC11 4.5.513.XP.MI. A marwacturer of fertilizer finds that national sales of fertilizer follow the seasonal pattern shown below, where is measured in pounds and represents the time in days, with corresponding to January 1. == 120,000 + sin 2t - 10 The manufacturer wants to set up a schedule to produce a uniform amount of fertilizer each day. What should this amount be? Su Are View Previous Question question 7 of 10 view Nee Question Home My Asments Request Extension

Answer 1

F = 120,000 4 + sin 20 (4-80) 365 365 total number of days in year = 365 Total fertilizer produced in 365 days = 120000 4+ sin 27 e-80) 12.0000 LAJ 120000 & sin 21 (1-80) i=1 365 365 = 120000 365 / = 480000 + 21767.4765 F = 501767.4765 for uniform production per day f" 501267.4765 365 f" = 1374.7054 pounds per days

int main() { float s=0; for(int i=1;i<366;i++) S+=120000*sin(2*3.14*(1-80)/365); printf("%f",s); return 0; } input 21767.476562