A sample of 1300 computer chips revealed that 47% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature states that 50%50% of the chips do not fail in the first 10001000 hours of their use. The quality control manager wants to test the claim that the actual percentage that do not fail is different from the stated percentage. State the null and alternative hypotheses.
Answer
Ho:
Ha:
Ho:p=0.50
that the actual percentage that do not fail is same as stated percentage
Ha: p not =0.50
that the actual percentage that do not fail is different from the stated percentage
Ha is claim
test statistic
z=p^-p/sqrt(p*(1-p)/n)
=(0.47-0.50)/sqrt(0.50*(1-0.50)/1300)
=-2.163331
Answer
Ho:
Ha
p value left tail is
=NORM.DIST(-2.163331,0,1,TRUE)
=0.015257865
2*left tail=two tial prob
2*0.015257865=
0.03051573
p<0.05
Reject Ho
Accept Ha
Conclusion:
There is suffcient statistical evidence at 5% level of significance
to conlcude that the actual percentage that do not fail
is different from the stated percentage.
ANSWER"
Ho:p=0.50
Ha:p not =0.50
A sample of 1300 computer chips revealed that 47% of the chips do not fail in...
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