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Help An IQ test is designed so that the mean is 100 and the standard deviation is 20 for the population of normal adults. Fin
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Answer #1

z value for 90% CI is 1.645 as P(-1.645<z<1.645)=0.90

Margin of Error is E=8

We will find n using formula of E

E=z*\frac{\sigma }{\sqrt{n}}

So n=(\frac{z*\sigma}{E})^2=(\frac{1.645*20}{8})^2=16.9=17

Yes. This number of IQ test scores is a fairly small number

So is the answer

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