Solve IVP by the Laplace Transform: y" + y = ezt , given y(0) = 0,...
Solve IVP by the Laplace Transform: y" + y = ezt given y(0) = 0, y'(O) = 1. a) Identify Y(s) = L{y} 3) Solve for y(t). Both of them a) Y (8) 21 + 3 52 +1 $-2 b) y(t) = } (e2t - cost + 3 sin t) 1 3 a) Y (8) 8 g2+1 + $-2 g²+1 b) y(t) = 22 cost + 3 sint None of them
Need Help with this Laplace transform Solve IVP by the Laplace Transform: y"+y=e2t , given y(0) = 0, y'(0) = 1. a) Identify Y(s) = L{y}. 3) Solve for y(t).
Given the differential equation y' + 367 - ezt, y(0) = 0, y'(0) = 0 Apply the Laplace Transform and solve for Y(s) = L{y} Y(s) = Now solve the IVP by using the inverse Laplace Transform y(t) = L-1{Y(s)} g(t) =
Use the Laplace transform to solve the IVP y"(t) + 6y'(t) + 9y(t) = e2t y(0) = 0 y'(0) 1
IVP Use the Laplace Transform to solve the y"+y = f(t) y'ld-o, y(0)=0 where f(t) = { 1 Oste/ sint tz /
The following IVP will be used for Question 1 and Question 2 on this quiz. Solve the initial value problem using the method of Laplace Transforms. y' - y' = 6x y(0) = 2,y'(0) = -1 The solution will be accomplished through answering the two questions below. In using the Laplace Transform to solve the above IVP, solving for Y(s) gives Y(8) = Y(s) = + 8+3 $-2 s-2 Y(s) – + 5 $+2 8-3 3 5 Y(s) = +...
If Laplace transform method is used to solve the IVP: y"(t) - 4 y'(t) + 4y(t) = 4 cos2t, yO)= 2; y'(O)=5 then the solution is: Select one: y(t) = e2t + sin2t - cos2t y(t)=2e2t + 2te2t_ 1 sin2t y(t) = 2te + cos2t - sin2t
Use the LaPlace Transform to solve the given IVP. y′′ + 4 y= -10e^−t y(=0) 0,−=y′(0) 4
Use the Laplace Transform to solve the IVP y" - y = 2e t, y(0) = 0, y'(0) = 1
Page 4 IV. (10) Use the Laplace transform to solve the IVP y" - 2y + y = f(t), y(0) = 1, y(0) = 1, where t<5 f(t) = t-5, t5 You may use the partial fraction decomposition 7(x2–2x+1) (6-1) + + - , but you need to show all the steps needed to arrive to the expression -16-28+1) in order to receive credit. f(t)=L-'{F(s) Table of Laplace Transforms F(s)=L{()} f(t)= L-'{F(s) F(s)=L{f(t)} 1. 2. et s-a 3. r", n=1,2,3,......