The reaction, 2NOBr(g) 2NO(g) + Br2(g) has an equilibrium constant, K = 0.42 at 373 K.
a. Calculate ΔGorxn at 373 K.
b. Using the value of ΔHorxn = 45.38 kJ and the ΔGorxn calculated in part a, calculate the ΔSorxn at 373 K.
Please show all work. Provide equations used for full credit. Please use correct significant figures and correct units in answers.
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
The reaction, 2NOBr(g) 2NO(g) + Br2(g) has an equilibrium constant, K = 0.42 at 373 K. a. Calculate...
Please show all work. Provide equations used for full credit. Please use correct significant figures and correct units in answers. The reaction, 2NOBr(g) = 2NO(g) + Br2(8) has an equilibrium constant, K = 0.42 at 373 K. a. Calculate Agºrxn at 373 K. b. Using the value of AHºrxn = 45.38 kJ and the AGºrxn calculated in part a, calculate the ASºrxn at 373 K.
Please show all work. Provide equations used for full credit. Please use correct significant figures and correct units in answers. The reaction, 2NOBr(g) + 2NO(g) + Br2(g) has an equilibrium constant, K = 0.42 at 373 K. a. Calculate AGºrxn at 373 K. b. Using the value of AHºrxn = 45.38 kJ and the AGºrxn calculated in part a, calculate the ASºrxn at 373 K. TT T Arial 3 (12pt) TEE >>>
Please show all work. Provide equations used for full credit. Please use correct significant figures and correct units in answers. The reaction, 2NOBr(g) + 2NO(g) + Br2(8) has an equilibrium constant, K = 0.42 at 373 K. a. Calculate Agºrxn at 373 K. b. Using the value of AHºrxn = 45.38 k) and the AGºrxn calculated in part a, calculate the ASºrxn at 373 K. Consider the reaction: 2NO(g) + C12(8) + 2NOCI(g) Given the following table of thermodynamic data,...
What is the equilibrium pressure At 373 K, Kp=0.416 for the equilibrium 2NOBr(g)?2NO(g)+Br2(g) If the pressures of NOBr(g) and NO(g) are equal, what is the equilibrium pressure of Br2(g)?
The equilibrium constant for the reaction: 2NO(g) + Br2(g) <----> 2NOBr(g) is Kc = 1.3x10^-2 at 1,000 Ka.) At this temperature, does the equilibrium favor the product or reactants?b.) Calculate Kc for 2NOBr <----> 2NO + Br2c.) Calculate Kc for NOBr <----> NO + 1/2Br2
For the following reaction, 2NOBr(g) <-----> 2NO(g) + Br2(g) the equilibrium constant Kp = 2.54×10-2 at 357 K and 3.57×10-2 at 381 K. Calculate ΔH° for the reaction, assuming no change in ΔH° between 357 K and 381 K. ΔH° = ________ kJ mol-1
Consider the reaction: 2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 130 torr and that of Br2 is 146 torr What is the partial pressure of NOBr in this mixture? Express your answer using three significant figures.
Consider the reaction: 2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 101 torr and that of Br2 is 150 torr . What is the partial pressure of NOBr in this mixture? Express your answer using three significant figures.
The equilibrium constant, Kp, for the following reaction is 6.25 at 298 K. 2NO(g) + Br2(g) 2NOBr(g) If ΔH° for this reaction is -16.1 kJ, what is the value of Kp at 187 K? Kp =
Consider the following reaction: 2NO(g)+Br2(g)⇌2NOBr(g) ,Kp=28.4, at 298 K In a reaction mixture at equilibrium, the partial pressure of NO is 102 torr and that of Br2 is 134 torr . Part A What is the partial pressure of NOBr in this mixture? Express your answer in torrs to three significant figures.