Question

2. How many triangle(s) can you make for each problem from the given information? Graph and show your work. Keep your answers in one decimal place calculator ok. a) A-65°, a = 18m b = 22. b) A=58°, a - 20, b = 22.

Answer 1

Quer 200) Giveu, A - 66°, a = 18m, b=22m from sine rule b SMB с. Smo SMA 22 2 ) 18 sm 65° c. smo SinB 2) Sin B2 22 Inbo -Sm B- 1.107 this is not possible, ance value of sine can not exceed I 80, eta no, arry triangle of such type is possible

b) A 2880 a 20, b=22 from line rule b ac hn B no SMA to 20 22 SMB c smo mo Sms8° 22 hrs 8o and ca 28 nB 2ohne Sms8° 20 es SMB = 0.9328.5 - Positive i B2 kn (0.93285) or 180° - 5m 10.9328.5) { .smon smo s posture either is first or second cond? quadrant B2 68.900 or 111.12 Now, if B= 68.900, foram eou angle recen properly A+B+C = = 1800 589768.90*+6 =180° -3C = 53.10° J B = 10.120 C2180-58-111-12° -10 2 10.88°) >> 6210.90 id E= 53.180, then, traum eyu o 206m 53.10 - ca 18.8 Sms8o 10.880, then fram eyno 20 Sim 10.88 zs sorc = 4.4 Smsso C =

are So, there two possible mangler A=580, B = (8:90°, 9°C 2 53.1° a=20, 6:22, C - 18.8 B a=20 c218.8 53.10 A 6=22 anel A=580 B² 111.10 - 10.9° a 220 b 222 C = 4.4 A b=22° 58 czu.4 10.90 B a=20