Solution) N = 170
r = 3.2 cm = 3.2×10^(-2) m
R = 5.8 ohm
Ns = 200 turns/cm = 200×10^(2) turns/m
ds = 4.5 cm = 4.5×10^(-2) m
di = 1.5 A
delta t , dt = 29 ms = 29×10^(-3) s
i = ?
E = - N(d(phi)/dt)
phi = B.A
B = (Uo)(Ns)(i)
E = - ((N)(Uo)(Ns)(As)(di/dt)
Uo = 4(pi)×10^(-7)
As = (pi)(rs^2)
rs = (ds/2) = (4.5/2) = 2.25 cm = 2.25×10^(-2) m
E = - [(170)(4(pi)×10^(-7))(200×10^2)(pi)((2.25×10^(-2))^2)(0-1.5)]/(29×10^(-3))
E = 0.35 V
i = (E/R)
i = (0.35)/(5.8)
i = 0.060 A
In the figure, a 170-tum coil of radius 3.2 cm and resistance 5.8 is coaxial with...
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Chapter 30, Problem 003
In the figure, a 180-turn coil of radius 2.6 cm and resistance
4.4 Ω is coaxial with a solenoid of 180 turns/cm and diameter 3.6
cm. The solenoid current drops from 2.1 A to zero in time interval
Δt = 23 ms. What current is induced in amperes in the coil
during Δt?
Chapter 30, Problem 003 Your answer is partially correct. Try again. In the figure, a 180-turn coil of radius 2.6 cm and resistance...
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As shown below, a 120-turn coil of radius 1.8 cm and resistance 5.3 2 is coaxial with a solenoid of 220 turns/cm and diameter 3.2 cm. The solenoid current drops from 1.5 A to zero in time interval At = 25 ms. a. What magnitude of current is induced in the coil during At? (17 pts) b. Does the induced current rotate in the same or opposite direction as the current in the coil? Justify your answer to receive credit....
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A coil with 170 turns, a radius of 5.0 cm, and a resistance of 12Ω surrounds a solenoid with 240 turns/cm and a radius of 4.5 cm ; see the figure. The current in the solenoid changes at a constant rate from 0 to 2.0 A in 0.15 s . a) Calculate the magnitude and direction of the induced current in the 170-turn coil. b) Which of the following is true? The current flows from left to right through the...