Homework Answers
3)
Test statistic = (n - 1) s2 / 
= (10 -1) * 28.4 / 27
= 9.47
4)
P-value = P(
21
> 34.7) = 0.0304
0.025 < p < 0.05
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QUESTION 3 9.3: Inferences about variance and standard deviation. Calculate the value of the test statistic,...
QUESTION 4 Given the test statistic and degrees of freedom, find the p-value range (area to...
QUESTION 4 Given the test statistic and degrees of freedom, find the p-value range (area to the right) that is the best choice. x2 = 34.7, df = 21 0.75 < P<0.90 0.05 <P<0.10 0.90 < P<0.95 0.025 <P<0.05 QUESTION 5 Given the test statistic and degrees of freedom, find the p-value range (area to the right) that is the best choice. x2 = 35.2, df = 24 0.90 < P<0.95 0.025 <P<0.05 0.75 <P<0.90 0.05 < P<0.10
Question 5 and 6 2 = 34.7, df = 21 0.75 <P<0.90 0.025 <P<0.05 0.90 <...
Question 5 and 6
2 = 34.7, df = 21 0.75 <P<0.90 0.025 <P<0.05 0.90 < P<0.95 О 0.05<P<0.10 UESTIONS Given the test statistic and degrees of freedom, find the p-value range (area to the right) that is the best choice. X2=2.76, df = 6 O 0.025 <P<0.05 0.05<P<0.10 0.90 <P<0.95 0.75 <P<0.90 QUESTION 6 When making inferences concerning the mean difference using two dependent samples, it is necessary to calculate the standard deviation of the sample differences Calculate the...
2 = 34.7, df = 21 0.75 <P<0.90 0.025 <P<0.05 0.90 < P<0.95 О 0.05<P<0.10 UESTIONS...
2 = 34.7, df = 21 0.75 <P<0.90 0.025 <P<0.05 0.90 < P<0.95 О 0.05<P<0.10 UESTIONS Given the test statistic and degrees of freedom, find the p-value range (area to the right) that is the best choice. X2=2.76, df = 6 O 0.025 <P<0.05 0.05<P<0.10 0.90 <P<0.95 0.75 <P<0.90 QUESTION 6 When making inferences concerning the mean difference using two dependent samples, it is necessary to calculate the standard deviation of the sample differences Calculate the standard deviation of the...
For the below output, what was the test used, the p-value and the conclusion? a. An F test...
For the below output, what was the test used, the p-value and
the conclusion?
a.
An F test, with 1 and 94 degrees of freedom; p
= 0.000;reject the null
b.
A chi-square test with 4 degrees of freedom; p = 0.383; do not
reject the null.
c.
A t-test with 91 degrees of freedom; p =
0.000; reject the null
d.
An F test with 4 and 91 degrees of freedom; p
= 0.000; reject the null
lSummary of...
Pick 3 correct inferences about the following hypothesis test to determine whether the mean thickness of...
Pick 3 correct inferences about the following hypothesis test to determine whether the mean thickness of aluminum sheets equals 0.05. Assume a 5% level of significance was used. A. The null hypothesis is mean 0.05". B. This is a one-tailed test. C. The chance of a Type 1 error is 1.4%. D, 68% of sheets should be +-0.01" of Hypothesis Test (One-Sample) Sample Size Sample Mean Sample Std Dev Hypothesized Mean Data Set #1 100 0.04739 0.01043 0.05 0.05 0.00104...
3) For the hypothesis test H0: μ = 5 against H1: μ < 5 with variance...
3) For the hypothesis test H0: μ = 5 against H1: μ < 5 with variance unknown and n = 12, approximate the P-value for each of the following test statistics. a) t0 = 2.05 b) t0 = −1.84 c) t0 = 0.4 EXPECTED ANSWERS: a) 0.95 ≤ p ≤ 0.975 b) 0.025 ≤ p ≤ 0.05 c) 0.6 ≤ p ≤ 0.75
For the below output, what was the test used, the p-value and the conclusion? a. An...
For the below output, what was the test used, the p-value and
the conclusion?
a.
An F test, with 1 and 94 degrees of freedom; p
= 0.000;reject the null
b.
A chi-square test with 4 degrees of freedom; p = 0.383; do not
reject the null.
c.
A t-test with 91 degrees of freedom; p =
0.000; reject the null
d.
An F test with 4 and 91 degrees of freedom; p
= 0.000; reject the null
lSummary of...
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations....
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations. Sample 1 Sample 2 x¯1=20.92 x¯2=26.80 s21=2.89 s22=3.81 n1=19 n2=15 Test the null hypothesis H0:μ1=μ2against the alternative hypothesis HA:μ1<μ2. a) Calculate the test statistic for the Welch Approximate t procedure. Round your response to at least 3 decimal places. b) The Welch-Satterthwaite approximation to the degrees of freedom is given by df = 27.983055. Using this information, determine the range in which the p-value...
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations....
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations. Sample 1 Sample 2 x¯1=20.08 x¯2=24.51 s21=2.05 s22=3.20 n1=19 n2=16 Test the null hypothesis H0:μ1=μ2against the alternative hypothesis HA:μ1<μ2. a) Calculate the test statistic for the Welch Approximate t procedure. Round your response to at least 3 decimal places. b) The Welch-Satterthwaite approximation to the degrees of freedom is given by df = 28.610808. Using this information, determine the range in which the p-value...
please solve and highlight answers Calculate the test statistic and p-value for each sample. Use Appendix...
please solve and highlight answers
Calculate the test statistic and p-value for each sample. Use Appendix C-2 to calculate the p-value. (Negative values should be Ind icated by a minus sign. Round your test statistic to 3 decimal places and p-value to 4 decimal places.) Test Statistic p-value (a) Ho: 0.50 versus H: T0.50, a 0.05, x= 48. n 81 (b) Ho: T 0.30 versus H: T # 0.30, a 0.05, x 18, n 39 (c) Ho: 0.10 versus H:...
QUESTION 4 Given the test statistic and degrees of freedom, find the p-value range (area to the right) that is the best choice. x2 = 34.7, df = 21 0.75 < P<0.90 0.05 <P<0.10 0.90 < P<0.95 0.025 <P<0.05 QUESTION 5 Given the test statistic and degrees of freedom, find the p-value range (area to the right) that is the best choice. x2 = 35.2, df = 24 0.90 < P<0.95 0.025 <P<0.05 0.75 <P<0.90 0.05 < P<0.10
Question 5 and 6
2 = 34.7, df = 21 0.75 <P<0.90 0.025 <P<0.05 0.90 < P<0.95 О 0.05<P<0.10 UESTIONS Given the test statistic and degrees of freedom, find the p-value range (area to the right) that is the best choice. X2=2.76, df = 6 O 0.025 <P<0.05 0.05<P<0.10 0.90 <P<0.95 0.75 <P<0.90 QUESTION 6 When making inferences concerning the mean difference using two dependent samples, it is necessary to calculate the standard deviation of the sample differences Calculate the...
2 = 34.7, df = 21 0.75 <P<0.90 0.025 <P<0.05 0.90 < P<0.95 О 0.05<P<0.10 UESTIONS Given the test statistic and degrees of freedom, find the p-value range (area to the right) that is the best choice. X2=2.76, df = 6 O 0.025 <P<0.05 0.05<P<0.10 0.90 <P<0.95 0.75 <P<0.90 QUESTION 6 When making inferences concerning the mean difference using two dependent samples, it is necessary to calculate the standard deviation of the sample differences Calculate the standard deviation of the...
For the below output, what was the test used, the p-value and
the conclusion?
a.
An F test, with 1 and 94 degrees of freedom; p
= 0.000;reject the null
b.
A chi-square test with 4 degrees of freedom; p = 0.383; do not
reject the null.
c.
A t-test with 91 degrees of freedom; p =
0.000; reject the null
d.
An F test with 4 and 91 degrees of freedom; p
= 0.000; reject the null
lSummary of...
Pick 3 correct inferences about the following hypothesis test to determine whether the mean thickness of aluminum sheets equals 0.05. Assume a 5% level of significance was used. A. The null hypothesis is mean 0.05". B. This is a one-tailed test. C. The chance of a Type 1 error is 1.4%. D, 68% of sheets should be +-0.01" of Hypothesis Test (One-Sample) Sample Size Sample Mean Sample Std Dev Hypothesized Mean Data Set #1 100 0.04739 0.01043 0.05 0.05 0.00104...
For the below output, what was the test used, the p-value and
the conclusion?
a.
An F test, with 1 and 94 degrees of freedom; p
= 0.000;reject the null
b.
A chi-square test with 4 degrees of freedom; p = 0.383; do not
reject the null.
c.
A t-test with 91 degrees of freedom; p =
0.000; reject the null
d.
An F test with 4 and 91 degrees of freedom; p
= 0.000; reject the null
lSummary of...
please solve and highlight answers
Calculate the test statistic and p-value for each sample. Use Appendix C-2 to calculate the p-value. (Negative values should be Ind icated by a minus sign. Round your test statistic to 3 decimal places and p-value to 4 decimal places.) Test Statistic p-value (a) Ho: 0.50 versus H: T0.50, a 0.05, x= 48. n 81 (b) Ho: T 0.30 versus H: T # 0.30, a 0.05, x 18, n 39 (c) Ho: 0.10 versus H:...
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