Question

University Physics II: Electricity and Magnetism

Class Textbook: Katz - Physics for Scientists and Engineers

Questions may involve the following topics:

Magnetic Fields and Forces/Faraday's Law of Induction/Inductors and AC Circuits

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3 of 4 A generator has 534 circular loops with a diameter of 0.234 meters. The magnetic field applied through the region where our loops will spin is 0.456 T. It outputs an average of 66 MW. Assume the generator circuit is the source as described above in an AC-RL circuit where R is the equivalent resistance Rey and the inductor L is an ideal transformer. 8. If the wire loops spin at 9.33x104 rev/min, what is the Vmax produced by the generator? 9. What are the values of Req and L, knowing that the max voltage drop across the transformer must be 95% that of Vmax? 10. Power is transmitted to a town 33 km away through 2 wires with a linear resistance rating of 0.11 2/km. What must the current be in these wires in order to lose only 1.6% of average power output by the transformer due to heating the transmitting wires? 11. Let's assume our ideal transformer has its secondary current as the value above. What would the number of turns in the secondary coil be if the primary has 888?

Answer 1

question 9. 33x10" hev/min Given datas in the - A Generator has 534 tinculat loops with diameter 0:234m The magnetic field applied through the region out loops will spin is 0:456 T. B and output an average of 66 MW. And generator circuit is described AL-RL Circuit and the L where R is the equallent Resiclance is an Ideal transformer (8) Given wire loops spin at 9:33x10 freu min. Then What is the Vmax produced by the generator ? voltage produce map. V may. = 2r o Ws $= magnetic thun and TR²=r S: D=0.234 (0.224) A=0.0430 m² 0 = {IT Mya) p=0.0196 wb { 1 min = 60 sec) seuls = B.A. 2 Area A- R = 0/2 0.456 X 0.0430 Ws = 1555 Now I may 27% 0.0496 x 1555 Vmax 191.50 volt

town of average power output by (10) now given power is troms mitted to a 33 km away through two wires with a linear resistance rating all rym. Then what must the Current be in there In order to loose only to heating the fronsmultry wines so total resistance of wire Collrx33 wires = 3.632 (Total) for two lones = 2 x 3.63 = 7.26 1.6 X 66 mW total power loss is 1.6% = = 1.6 x 66x100w 100 loss equal I'R and we we know that so 6 1:6 = 1²x X 7.26 x 66 x 10 100 I - 381.3850 Amp. CS Scanned with Camsdanner

(11) value lebore Let's assume our ideal fremsformer has its Seconslary curent the Then What would the number of turns n the Secondary Coil be if the If the primary has 885 Given as current m econdary (Is) = 381-3850 Amp Mo of turns in secondary coil Me = ? (find) No. of turns in primary No: seco 885 we ( from & question know that I p = 3 44 64 k Amp Is Mp Also know that Ip Mg 344.64 K amp Ms = Mp ( lp Is 5 888 X 381.3850 Dop ( fp 4 Is from 0.40 o) No a 802 444 Seenhed withi (This is the tumes in secondary coil)
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