Ans. t critical value with degrees of freedom of 12 (14-2) and confidence level of 95% = 2.17881
and Point estimate = b0 = 41.23
Standard error = se = 14.9
=> Margin of error, M = t*se = 2.17881*14.9 = 32.4642
95% confidence interval of B0 = [b0 - M, b0 + M]
=> 95% confidence interval of B0 = [41.23 - 32.4642, 41.23 + 32.4642]
=> 95% confidence interval of B0 = [8.766, 73.694]
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