Question

(25pts) The 0.5in.-diameter hose shown in Figure can withstand a maximum pressure of 300 psi without rupturing. Determine the maximum length, 1, allowed if the friction factor is 0.022 and the flowrate is 0.020 f/s. Neglect minor losses Nozzle tip diameter - 0.30 in. y = 62.2 lb/ft3 D-0.50 in. P2 = 0 Water 10 ft 3 ft Pump

Answer 1

10.1 Pump .L Given- Diometom of Fine d05 in = 0.0424 Pressure at fections, P4 = 300 Psi = 43200 lb Pressure out section & P2 = opsi = 0 lb It? velocity at nation, 142 U Al 0.02 0.5.12 12 4 Vg 4 0.02 K 40:14H/ VRE A2 0.312 4 and I = 0 ft Zq = 10ft 2.2 4452 9 = 3412 62.2 16/03 pg

Apply conservation of Energy - PA +7+ va P2 + Z₂ + 1 2 2 9 a the eg 2 Here, hi 0-099XIX (14-6-1) 2x32.27 0.042 lody ht=175) Now, Substitute all the values in the above cavation. (14.67) 2 43200 62.2 tot = 0+10+ (40.74) +1.75 l 9 x 32.2 2 X 32.2 694.54 +3.35 = 10+ 25.77 +375) - 378.35 ft And