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ZnC4H10 is liquid that spontaneously undergoes combustion in the presence of air according to the following...
ZnC4H10 is liquid that spontaneously undergoes combustion in the presence of air according to the following equation ZnC4H10 (l) + O2 (g) ---> ZnO (s) + CO2 (g) + H2O (g) Balance the equation. Calculate w and Δ E when 2 mol of liquid ZnC4H10 is vaporized at 265 K and 760 mm Hg. The Δ H vaporization is 39.9 kJ/mol at 265 K.
Calculate w and ΔE when 2 mol of liquid ZnC4H10 is vaporized at 265 K and 760 mm Hg. The ΔH vaporization is 39.9 kJ/mol at 265 K.
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pt) A sample of 1.0 mol of liquid octane C8H18(1) undergoes combustion accord 5. (10 pt) A C3H18(0) + O2(g) → 8 CO2(g) + 9 H2O(l) Using the standard enthalpies of formation given calculate the change in enthalpy in kJ/mol associated with the combustion of 1.0 mol of C8H18(1) at 1.0 bar pressure and 25 °C. Substance AH® (kJ/mol) C8H18() -249.9 CO2(g) -393.51 H2O) -285.83
Question 3 Propane (C3Hg) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) - 3 CO2(g) + 4H2O(g) AHrxn=-2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3Hg a. -104.7 kJ/mol O b. +1407.7 kJ/mol O C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol uestion 4 Consider the evaporation of liquid water to water vapor at 125°C. What is true...
Question 3 Propane (C3H8) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) -- 3 CO2(g) + 4H2O(g) Arxn = -2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3H8 a. -104.7 kJ/mol ob. +1407.7 kJ/mol C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol
1. Calculate the enthalpy of combustion (in kJ/mol) for propane, which burns according to the following equation: C3H8(g) + 5 O2(g) + 3 CO2(g) + 4H2O(1) AH® (C3H8) = -104.63 kJ/mol
The combustion of lauric acid is given by the following
thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) +
12 CO2(g) Hcomb is −7377 kJ mol−1 Using the heats of formation
for CO2(g) and H2O(l) calculate the heat of formation (△fH) of
lauric acid. △fH△ CO2(g) = −393.5 kJ mol−1 fH
H2O(l)= −285.8 kJ mol−1
19. The combustion of lauric acid is given by the following thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) + 12 CO2(g) AH...
Time Taken:0:33:09 Brandon Bates: Attempt 1 MULUI PUT Ethanol undergoes combustion in oxygen to produce carbon dioxide gas and liquid water. Standard enthalpy formation of [CO2(e)] = -393.5 kJ/mol and [H20(1)] = -285.8 kJ/mol, C,H,OH(1) = -277.6 kJ/mol, what is the standard enthalpy of combustion of ethanol? kJ C,H, OH(1) + 3 02(g) + 2 CO2(g) + 3 H2O(l); A Hex = AH, /mol AH° (ræn) = In A Hfº (products) - In AHF ° (reac tants) +2349 kJ/mol +1366.8...
can you do the 7 and 9 ? can you also show and explain
me step by step?
D. 49.6 kJ E. 57.3 kJ 7. Butane (C4H10) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. Given AH° [C4H10(g)] = -124.7 kJ/mol, AH° [CO2(g)] = -393.5 kJ/mol, AH [H2O(g)] = -241.8 kJ/mol, how much energy is released (kJ) when 8.30 g of butane is burned? Combustion of butane: 2 CH2(g) + 13 O2(g) → 8 CO2(g) +...
6) Naphthalene (CoHs; MM-128.2g/mol) is a solid aromatic compound often sold as mothballs. The complete combustion of naphthalene into CO:(g) and H2O () at 25 °C produces 5154 kJ/mol of heat A) Write a balanced chemical equation for the complete combustion of naphthalene. B) When 55.5 grams of naphthalene undergoes combustion with 4mol O, how much heat is produced? (Consider the sign of the enthalphy.) C) Write a balanced chemical equation for the formation of naphthalene (CoHs) from its elements...