Question

III. Procedure: A charged body having charge Q = 0.002 C, mass M= 0.004 Kg, was initially held at rest at a voltage line located at height=H=D= 2m. Varying amounts of voltages were applied at the voltage line. The time the charged body took to fall to the zero-voltage level of the ground were measured using a digital smart timer. Attracted by the electrical force, the charge falls to the zero-voltage ground in the indicated times. Since the electrical forces on the charge are stronger than gravity, gravitational forces are negligible. (1) For each row, showing your steps on a separate attached paper, calculate the initial mechanical energy (E) of the charge, the acceleration of the charge and the final mechanical energy (Et) of the charge. Fill in your answers in the table. (2) For each row, calculate the percent difference between initial mechanical energy (Ei) and final mechanical energy (Ef). IV. Raw Data: The voltages applied, and the corresponding falling times of the charged particle are indicated in the raw data table below Voltage (V) Time (s) Initial Mech. Energy (E)(Joules) Acceleration(m/s) Final Mech. Energy (Ec)(Joules) 200 0.280 400 0.191 600 0.165 800 0.149 1000 0.132 INITIAL ENERGY-FINAL ENERGY Percent difference = INITIAL ENERGY+FINAL ENERGY -X 100 %

Answer 1

Voltage (V) Time (s) Initial Mech. Energy (E) (Joules) a = Q v Acceleration(m/s) Final Mech. %. diff. Energy (E.) Joules) E:-Ef prool? 5.5 Rvx E;= .v 200 0.280 50 0.392 2.027 400 0.191 2. 327 600 0.165 0.729 1:225 112 150 - 2.061) 800 0.149 HG - 10.4 1.776 2:178 1000 0.132 20 250 1-8-529 INITIAL ENERGY-FINAL ENERGY Percent difference = INITIAL ENERGY+FINAL ENERGY Ooons x V²2² X 100% D-002 2 V=8 Hcam . M. o.oon ng Neglecting the effect of gravity, Fone acting F = QE d is d on charge a 2 ) Q V 1H-0) Q. v Heom VOV И. a Mill QV.4 Shi V- af thit talen F IQ.N Acceleration of charged particle Velouty of charge particle when reaching nom, Initial mechanical Energy Ei Pitki = QNto Q.V 12 MA. V2 = ² final mechanical eneron, Q²v2.12 QV tiz Canada HM Substituting for different values V200 E: - O' 102 mio. OYJ as 0.002. ► 20 50 m2 0.00472 Ef - • 5 xeotoko) = 0.392 3 2 V-400 F; O'rmowa 0.85 a OU OU x400 lumapi? Do not myx6.1992 0.7299 3 v: 600 Ei : 00026n 9 - 062 600 150 mp² Oy Ovons (bvo) (O.162 = 112255 3 usoo O 165 a 072 -> o 0.42 Wom i Ve loro E = oror amo: 2.09 conomy ((0.142 1-770 I a 2012 honor wompr 0.00479 0.000m (Tuto24(0:132) 2.1785