Question

A box with a mass of 1.80 kg slides along a flat track with friction until it makes contact with a horiztonally mounted spring. At the instant that the box makes contact with the spring the box has a velocity magnitude of 2.00 m/s. The box slides and slows down until it comes to a rest after compressing the spring 11.0 centimeters.

If the coeficient of kinetic friction between the track and box is 0.56, what is the spring constant of the spring?

less than 400 N/m

greater than between 520 N/m

between 440 and 460 N/m

between 400 and 420 N/m

between 460 and 480 N/m

between 500 and 520 N/m

between 420 and 440 N/m

between 480 and 500 N/m

Answer 1

V= 2 m/s m= 1.8kg re, = 2 m/s x=11cm Drawing FBD og MR = 0.56 n wted the box. 0= عهد اله llem, fo mg fx friction force - M.N=Manga If spring force According to work energy theorem Whate = AKE KE-KE; Here KE=0 [ 0 =0 Wina - fax 2 Copposite force & motion] ffene son so wkt Wfs Now -fax a + ( - 2 Rx² = - 2 m 3

Date Page 3x4-8427' (0-55x+349.0)+(4xRKHX1623) X 11x10² xkx44x462)2 = 2054 k= 414.87 N/m between 400 & 420 N/m option D is correct.