Homework Answers
f(x) = x^3 - 8x^2 + 16x
Setting f(x) = 0
x^3 - 8x^2 + 16x = 0
x ( x^2 - 8x + 16 ) = 0
x ( x - 4)^2 = 0
Setting each factor to 0
x = 0 , x - 4 = 0
x - 4 = 0
Add 4 on both sides
x = 4
| The zeros are 0 ( multiplicity 1 ) , 4 ( multiplicity 2 ) |
The graph crosses the x axis at x = 0
The graph touches the x axis at x = 4
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