A light ray in air strikes the right-angle prism shown in the figure (Figure 1) (ZB=30.0)....
The light ray in the figure below strikes the hypotenuse of the prism at an angle of incidence greater than the critical angle. Find the angle phi of the ray as it leaves the base of the prism. The incident ray is perpendicular to the left side of the prism. (The index of refraction of the prism is 1.5. Take θ to be 44.9°.)
The light ray in the figure below strikes the hypotenuse of the prism at an angle of incidence greater than the critical angle. Find the angle ϕ of the ray as it leaves the base of the prism. The incident ray is perpendicular to the left side of the prism. (The index of refraction of the prism is 1.5. Take θ to be 43.8°.)
Glass Prism in Air: Rays A and B approach the equilateral prism, and the prism is glass surrounded by h indexes of refraction shown. Following the rules of geometrical optics, trikes a trace each ray as it reflects and refracts at the prism's surfaces. If a ray s surface and undergoes both reflection and refraction, then only trace the refraction. Continue tracing each ray until the ray is moving away from the prism As each ray strikes a surface, record...
An incident coherent light ray strikes the interface between two different media with indices of refraction n1 and n2 (see figure below). Part of the ray gets reflected, and part of the ray gets refracted. Based on the information shown in the figure, which of the following is true? Let v1 and v2 be the speed of light in media 1 and 2, respectively. v1 < v2 v1 = v2 The reflected ray undergoes no phase shift relative to the...
A light ray in air (n= 1) is incident on a thin film of oil (noil = 1.60) floating on top of water (nwater = 1.33), as shown below. The wavelength of the incident light in air is Aair = 640 nm. The oil layer has a thickness t = 0.5 um. The ray is assumed to be incident practically along the normal. That is, we won't be worried about angles of reflection or refraction when doing this problem. However,...
water interface (the surface of the lake), it is partly reflected back into the air and partly refracted or transmitted into the water. This explains why on the surface of a lake sometimes you see the reflection of the surrounding landscape and other times the underwater vegetation. These effects on light propagation occur because light travels at different speeds depending on the medium. The index of refraction of a material, denoted by n, gives an indication of the speed of...