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40 F (N) 30 20 10 20 40 d (cm) A force, shown in the graph above, is applied to a block of mass, m = 2.3 kg that is initially
Question 2 4 pts A 3.00 meter long bar that has a mass of 14.0 kg is supported by a cable that makes an angle of 30.0 degrees
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Answer #1

(1) K.E. = Area of graph = change in mv²-0 x 2.3 x v? 4x0.2x40+ *(40+20)*0.2 2 2 4 + 6 10 v= 2.95 mis Answer (27 Balanung mom

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