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This Question: 1 pt UML JU Tules - Taken 31 of 36 (0 complete The Remag 01:14:12 This Test: 3 Intelligence quotas on two diff
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Answer #1

A ~ normal with mean 100 and std. 18 and B ~ normal with mean 100 and std. 16.

Now, p(A>128) = P((A-100)/18 >(128-100)/18)

= P(z>28/18) = P(z>1.56) = 0.059

And P(B>122) = P((B-100)/16 > (122-100)/16)

= P(z> 1.38) = 0.084

As probability of A greater than 128 is lower means 128 score in test A is tough than 122 in test B.

Hence, it has more iq

Hence, option a) is correct.

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