Consider the solution to the IVP y' - xy = x; y(0) = 2 Find y' (0) Consider the solution to the IVP y' - xy = t; y(0) = 2 Find y" (0)
Consider the solution to the IVP 9 – = ; g (0) = 2 Find y" (0) Consider the solution to the IVP tư – (g)? = 0; }(0) = 1; / (0) = 2 Find the coefficient of 25 in its Taylor expansion centered at 0.
Question 2 2 pts Consider the solution to the IVP y - ry=2; y(0) = 2 Find y' (0) Question 3 2 pts Consider the solution to the IVP y - ry=r; y(0) = 2 Find y" (0) Question 4 4 pts Consider the solution to the IVP w"-() = 0; y(0) = 1; 7 (0) = 2 Find the coefficient of in its Taylor expansion centered ato.
Consider the solution to the IVP yy" – (y)2 = 0; y (0) = 1; y (0) = 2 Find the coefficient of 25 in its Taylor expansion centered at 0.
Consider the IVP y" - 4y' + 4y = 0, y = -2, y'(0) = 1 a. Solve the IVP analytically b. Using step size 0.1, approximate y(0.5) using Euler's Method c. Find the error between the analytic solution and the approximate solution at each step
Find the solution of the IVP (3x^2 + y^2) + (2xy + cos y) y' =0 ; y(2)=0
Question 1: [25 pts] Consider the IVP y" – 4y' - 5y = 0, y(0) = 1, y0) = 2. a) Find the solution of the given IVP using the corresponding characteristic equation. b) Find the solution of the IVP using the Laplace Transform. c) Does the solution change if we would change the second initial condition as y'(0)=3? Explain.
. Consider the IVP y'= 1 + y?, y(0) = 0 a. Solve the IVP analytically b. Using step size 0.1, approximate y(0.5) using Euler's Method c. Using step size 0.1, approximate y(0.5) using Euler's Improved Method d. Find the error between the analytic solution and both methods at each step
Consider the following IVP y″ + 5y′ + y = f (t), y(0) = 3, y′(0) = 0, where f (t) = { 8 0 ≤ t ≤ 2π cos(7t) t > 2π (a) Find the Laplace transform F(s) = ℒ { f (t)} of f (t). (b) Find the Laplace transform Y(s) = ℒ {y(t)} of the solution y(t) of the above IVP. Consider the following IVP y" + 5y' + y = f(t), y(0) = 3, y'(0) =...
a=0 find the solution of IVP y" +(a +1)y = e(6+1)t, y(0) = 0,4(0) = 2 using Laplace transform.