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26. What is the pH of 10 M Na Sos(aq) at 25 "C?(K1 - 1.2 x 10 KA-6.2 x 10 ) a. 3.40 b. 6.03 c. 7.96 d. 10.40 e. 10.60
a) If the Kb of a weak base is 4.8×10−6, what is the pH of a 0.46 M solution of this base? b)A certain weak base has a Kb of 8.90×10−7. What concentration of this base will produce a pH of 10.35?
What is the pH of a 12.5 M solution of H2SO,? The first proton completely dissociates; the K, for the second proton is 1.2x10-2 Answers must be accurate to 2 decimal places. Multiple tries are permitted; however, 20% (1/5) point will be deducted for each incorrect response.
What is the pH of a 13.5 M solution of H2SO? The first proton completely dissociates; the K, for the second proton is 1.2x10-2 Answers must be accurate to 2 decimal places. Multiple tries are permitted; however, 20% (1/5) point will be deducted for each incorrect response.
An enzyme binds to a competitive inhibitor with Kd = 1.2 × 10-6 M at pH 7.0 and 25°C.(a)At what inhibitor concentration will 75% of the enzyme be bound to the inhibitor if there is no substrate present? (b) This enzyme has a Km of 4.0 × 10-5 M and a Vmax of 50 μM/s. At a substrate concentration of 3.0 × 10-4 M, calculate (i) the velocity of reaction in the presence of the inhibitor at 4.8 x 10-5 M (ii) the degree of...
1. The pH of a HA/A = 1/10 buffer is (pKa 4.8) (A) 4.8 (B) 5.8 (C) 5.85 (D) 5.9 (E) 6.0 2. Which of the following values is closest to the pH of 10 M NaOH (A) 11 (B) 10 (C) 8 (D) 12 (E) 9 3. The pH of a solution containing 0.01 M HCl plus 0,04M KCIO, is: (The activity coefficient of H' in this solution is 0.86) (A) 2.07 (B) 1.97 (C)3.00 (D) 1.00 (E) 2.04...
Calculate the pH of a 0.002 M H2SO4 solution. Ka for H2SO4 is 1.2*10^-2.
If the Ka of a monoprotic weak acid is 2.4 x 10-6, what is the pH of a 0.45 M solution of this acid? pH =
3. (10 pts) What does the following statement represent? pH=- log (1.2 M) 4. (10 pts) How does the pH probe determine the pH of a 6.0M solution of HNO,?
Determine pH and pOH of a 1.2 X 10-2 M aqueous solution of sodium fluoride.