Question

09:58:19 Time Remaining Return Next 3 2 points A major motor company displays a die-cast model of its first automobile, made from 6.46 kg of iron. To celebrate its one-hundredth year in business, a worker will recast the model in gold from the original dies. What mass of gold is needed to make the new model? Use Table 9.3 in the book for the data needed to solve this problem. Give your answer in Sl units and to the correct significant figure. Type your answer... Previous Next ans Preferences 5 6 7 8 9 0. R. T U 0 Р

Answer 1

0.821 x 103 - mi = 6.46 kg =) density of Peron, di = 1.86 x 103 kg lm3 density of gold, dg = 19.30 x 103 Kg 1m3 Volume of die model V = mi di 6.46 7086x10 * cast is, 3 mi V - * volume of die cast model remains Constant for leon iron and gold,

→ Mass of gold hequred for new model is, mg = Vdg -(0.821 x103) (19.30 x103) 8 mg = 15.86 kg - mass of gold for new model, mg -15.86 kg