Question

Consider this circuit. Which of these equations is correct? 422 Ω -6 V Tom IX Hr 32 12 V kul Now choose from one of the following options Why? a 11 + 12 = 13 b -412 + 6 + 12 +213 = 0 C 311-4-213 + 12 = 0 d 4 - 311 + 6+ 413 = 0 e 13 + 12 = 11

Answer 1

A B С -40 { 11 -6 V I'm 13 F w 30 E D 12 V

Applying Kirchoff's voltage law in ABEF,

$4-3I_1-6+4I_2=0$

-311 -2+412 = 0

Applying Kirchoff's voltage law in BCDE,

$-4I_2+6-12+2I_3=0$

Applying Kirchoff's voltage law in ACDF,

$-2I_3+12+3I_1-4=0$

$4-3I_1-12+2I_3=0$

From the above three equation we can find the relation between $I_1,I_2$ and $I_3$ .

  $-4I_2+6-12+2I_3=-3I_1-2+4I_2$

  $3I_1+2I_3=4+8I_2$

Hence from al the above equation we can say that option c is correct