Question

18) A bee speeds up for 10 second as it flies, the bee's change in velocity is given by the velocity vectors, what is the magnitude and direction of acceleration of the bee? 7p = (+20 m/s) + (+15 m/s)9 +(-8 m/s)2 7=(+ 8 m/s)X + (+2 m/s)9 + (+5 m/s)2 19) A jet airplane (mjet -2,000 kg) slows down in three-dimensional space for 10 seconds, the jets initial and final velocities are given below, what is the magnitude of the jets acceleration and what is the net force acting on the jet as it acceleration? vp = (+ 5 m/s)X + (-10 m/s)9 + ( 0 m/s)2. = (+ 15 m/s) + (-20 m/s)9+ (+15 m/s)2

Answer 1

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In first question direction of acceleration, I have found in terms of unit vector as there is no reference given in question.

12 i +13 9 - 1312 t lo clal- 1:22+1 3+1:32 - 2-19 acceleration, as a = 1.21 +1:33-1.3k lal= 2.19 m82 Direchon of a can be represented in terms of onit veckr 1.2 i +1:37 -1.31 Tal Unit veeker = 0.5h7i+0.592 ] - 0.592 k a will act in the direchon of above unit vector 19) acceleration = Fs-vi/t=-10% Hoi - 158 a=-1 it û 1.5k P+ 2 +1.5² = 2.06 ms² Neffore = ma= 2000 (-11t in + û - 1.51) frey = 62000| +20009 - 30001 ) N lo alla 2000xlal = h123.10N 2 Fred) = miah