ZuoTi.Pro
Question
please help

Question 16 10 p Exoplanets A and B are observed to orbit Star X in circular orbits at distances 1.1 AU and 10.2 AU from Star
science   physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

\!\!\!\!\!\!\!\!\!$Centripetal force for moving in circular path is provided by the gravitational force.$\\\\ \frac{m_Av^2}{R} = \frac{Gm_Am_X}{R^2}\;\;\;\Rightarrow \;\;\; v = \sqrt{\frac{Gm_X}{R}}\\\\ $Time period of exoplanet A is given by, $\\\\ T = \frac{2\pi R}{v} = 2\pi R\sqrt{\frac{R}{Gm_X}}\\\\ $Mass of Star X is given by, $\\\\ m_X = \frac{4\pi ^2R^3}{GT^2}= \frac{4\pi^2\times (1.1\times 1.5\times 10^{11})^3}{6.67\times 10^{-11}\times (244\times 86400)^2}= 5.98\times 10^{30}$kg$

0 0
Add a comment
Know the answer?
Add Answer to:
please help Question 16 10 p Exoplanets A and B are observed to orbit Star X...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Question 16 10 pts Exoplanets A and B are observed to orbit Star X in circular...

    Question 16 10 pts Exoplanets A and B are observed to orbit Star X in circular orbits at distances 1.1 AU and 10.2 AU from Star X, respectively ( 1 AU = 1.5 x 1011m). The orbital period of Exoplanet Ais 244 days. What is the mass of Star X? (1 day = 86400 s.) 1.0 x 1030 kg 2.5 x 1030 kg O 1.5 x 1030 kg 2.0 x 1030 kg 3.5 x 1030 kg 4.5 x 1030 kg...

  • Question 16 Exoplanets A and B are observed to orbit Star X in circular orbits at...

    Question 16 Exoplanets A and B are observed to orbit Star X in circular orbits at distances 1.1 AU and 10.2 AU from Star X, respectively ( 1 AU = 1.5 x 1011 m) . The orbital period of Exoplanet A is 244 days. What is the mass of Star X? (1 day = 86400 s.) Group of answer choices 2.5 x 1030 kg 4.0 x 1030 kg 5.0 x 1030 kg 3.5 x 1030 kg 1.0 x 1030 kg...

  • please help there is a typo period should be radius Question 17 10 pts [Continued from...

    please help there is a typo period should be radius Question 17 10 pts [Continued from Question 16.] Exoplanet B orbits Star X with an orbital period 10.2 AU. What is the distance of Exoplanet B from Exoplanet A during opposition (when Exoplanet A and Exoplanet B are aligned on a line passing through Star X on the same side of Star X)? 9.1 AU 5.7 AU 10.2 AU 1.1 AU 20.4 AU 5.1 AU 22.6 AU O 11.3 AU...

  • Exoplanets A and B are observed to orbit Star Xin circular orbits at distances 1.1 AU...

    Exoplanets A and B are observed to orbit Star Xin circular orbits at distances 1.1 AU and 10.2 AU from Star X, respectively ( 1 AU = 1.5 x 1011 m). The orbital period of Exoplanet A is 244 days. What is the mass of Star X? (1 day = 86400 s.) O 1.0x 1030kg O 5.0x 1030 kg 04.0x 1030 kg 3.0 x 1030 kg O 2.5 x 1030 kg O 3.5 x 1030kg O 4.5 x 1030 kg...

  • Question 16 Exoplanets A and Barberved to orbe Star Xin circular orbits a distances 11 AU...

    Question 16 Exoplanets A and Barberved to orbe Star Xin circular orbits a distances 11 AU and 102 AU from Star X respectively ( 1 U - 15 x 10" Theor period of Exoplanet Ais 24 days. What is the mass of Star X11 day 400 50x10 45x10 150 20x10 1010 35.10 40x10 30.10 2.510

  • A 3.0 x 1021 kg moon orbits a distant planet in a circular orbit of radius...

    A 3.0 x 1021 kg moon orbits a distant planet in a circular orbit of radius 1.5 × 108 m. It experiences a 1.1 X 1019 N gravitational pull from the planet. Part A What is the moon's orbital period in earth days?

  • A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x...

    A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x 1030 kg. Consider the orbit of the planet to be circular and the star is at the center. The distance between the star and the planet is 1.496 x 1011 m. Calculate the orbital velocity of the planet. (G=6.67x10-11 mº kg1s 2) (In the choices below, 10^4 is 104) O 2.99 x 10^4 m/s 8.92 x 10^4 m/s O 4.58 x 10^4 m/s O...

  • please show work 7. 1.1/3.1 points Previous Answers CJ10 8.P.047. A planet orbits a star once every 3.29 x 10's in a...

    please show work 7. 1.1/3.1 points Previous Answers CJ10 8.P.047. A planet orbits a star once every 3.29 x 10's in a nearly circular orbit of radius 1.53 x 1011 m. (a) With respect to the star, determine the angular speed of the planet. X rad/s (b) with respect to the star, determine the tangential speed of the planet. 29219.7 m/s (c) with respect to the star, determine the magnitude and direction of the planet's centripetal acceleration, magnitude m/s2 direction...

  • please help me solve part B it is drawing please be clear To use a load...

    please help me solve part B it is drawing please be clear To use a load diagram to determine internal axial forces and to calculate axial deformations. The axially loaded bar with circular cross-section is loaded and supported as shown below. The bar is made of aluminum 2014-T4 and has a modulus of elasticity, E, of 10,600 ksi. The lengths of segments AB, BC, and CD are 2, 1.5, and is 2.5 ft, respectively and the diameters of the segments...

  • could you please use the ksp values from this list question. Solid magnesium hydroxide and solid...

    could you please use the ksp values from this list question. Solid magnesium hydroxide and solid cobalt(II) hydroxide are in equilibrium with a solution containing 1.18x10-2 M magnesium nitrate. Calculate the concentration of cobalt(II) ion present in this solution. [cobalt(II)] = M LU Substance Aluminum compounds Substance 1.6 X 10-16 1.9 X 10-33 1.3 x 10-20 7.8 x 10-21 6.7 X 10-31 2.4 x 10-23 1.6 X 10-9 Chromium compounds CrAsO4 CH(OH), СТРО. Cobalt compounds Co (AsO.) COCO, Co(OH), CoS...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT