Question

The 5-Mg bus B is traveling to the right at 20 m/s. Meanwhile a 2-Mg car A is traveling at 15 m/s to the right. If the vehicles crash and become entangled, determine their common velocity just after the collision. Assume that the vehicles are free to roll during collision. VB = 20 m/s B VA = 15 m/s A

Answer 1

Let us before assume that momentum will be conserved after and collision VB = 20 m/s B VA = 15 m/s А ma= 2 Mg = 2x10² kg mg = 5 Mg = 5x103 kg VA = 15 ms -1 VB = 20 ms-l let the so, com mon velocity be v after collision. According to momentum conservation, MAVA AMB VB = (MA MB) 2000 x 15 + 5000X 20 = (2000+ 5000 v 7000 V = 130000

130 = 18.57 ms-1 = V= 130000 7000 So, the common velocity after collision will be 18.57 ms -!