Question

The demand for a new computer game can be modeled by p(x) = 58 -8 In x, for 0 5x5 800, where p(x) is the price consumers will pay, in dollars, and x is the number of games sold in thousands. Recall that total revenue is given by R(x)=x.p(x). Complete parts (a) through (c) below. a) Find R(x). R(x) = b) Find the marginal revenue, R'(x). R'(x)=0 c) How many units will be sold if the price that consumers are willing to pay is $40? The number of units that will be sold is 17 (Round to the nearest whole number as needed.)

Answer 1

Ginen, demand a new computer game for modeled by - can be P100 = 58 8 ln(a) 0 < X < Seo P(a) Where the price, Consumer will pay. (a) To find Rene) R(a) e P(ae) Ria) x [ 58 - 8 11 12e)] R(2) 582 - 82 Ince) Answer 2 (b) To To find Marginal Revenue, Rix have, we 584 - 8 se R (1) lu(x) Differentiate worst wort. W Rex) = (582- 8xe lube)

Rías (58%)' - (8 x In l2))' Rox) 580 - 8 [xlnews]' Rix) = 58 - 8 58 - 8 [ x Clucro)' + (ln(x). x] Read 58 -8 [ { x ++ (lucoes). 1] Rex) 58-8 [1 + lu(x)] R'(x) = 58-8-8 Inca Real 50 - 8 ln (2) Answer is Consumer Given (VC) willing to pay $40 Pra) le. 40 58 =) 40 8 ln x - 40-58 ㅋ -8 ln xe -8 ln x -18 I Inca) 11 18 8

=) In lw= 2.25 2.25 -> 2 x 9.48773584 (approx) No. of unite that will be Solned = १ Auswer.