007 (part 1 of 2) 10.0 points A proton travels with a speed of 3.08 x...

Question

Question

007 (part 1 of 2) 10.0 points A proton travels with a speed of 3.08 x 10 m/s at an angle of 29.1° with a magnetic field of 0.

Answer 1

Answer #1

A F = quB sino Given, 6 U= 3.08 X10 O = 29.1° B = 0.451 T (1.6 0 218 x 10 6 - 19) * (3-08x10 )(0.451) Sin69.1) 13 1.0823 X10

Answer 2

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