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Investigators working on commericially cultivating shrimp are interested in determining the best conditions in which for themThe investigators want to know whether there is an interaction between temperature and salinity. Which of the following wouldWhat is the grand mean? [1 pt(s)] Tries 0/3 Submit Answer Calculate the degrees of freedom Temperature Interaction Error [1 pDo we reject the null hypothesis of their being an interaction at significance level a = 0.1? Yes, reject the null hypothesis

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Answer #1
row and coulmn means=Σ x̅i/Σni
A B C D row total means nj SSA=nj( x̅j - x̅̅)²
1 50.05 67.34 58.695 6 6*(58.695-71.7933)²=1029.398
2 72.42 89.55 80.985 6 6*(80.985-71.7933)²=506.9204
3 63.04 88.36 75.7 6 6*(75.7-71.7933)²=91.5723
4
column total means 61.83666667 81.75 71.79333
ni 9 9
SSB=Σni( x̅i - x̅̅)² 9*(61.8367-71.7933)²=892.2169 9*(81.75-71.7933)²=892.2169

(aBij = 0 for all ij

================

ALTERNATE-

(abij 0 for some ij

=============

grand mean , x̅̅ =    71.793

=========

sALINITY= dfA = r - 1 =    3-1=   2
Temperatire = dfB = c-1 =    2-1=   1
Interaction = dfAxB = (r-1)*(c-1) =    2*1=   2
Error = dfE = N-rc=   18-3*2=   12
---------------

SSbetween=n( x̅ - x̅̅)²=       3478.1158
SSA=Σ nj( x̅j - x̅̅)²=   1029.398+506.9204+91.5723=   1627.8907
SSB=Σ ni( x̅i - x̅̅)²=   892.2169+892.2169=   1784.4338
SS AxB= SS between-SSA-SSB=       65.7913
SSE= 12.8155

MSAxB = SSAxB/dfAxB =    65.7913/2=   32.8956
F for interaction =    MSAxB/MSE =    30.8024  

yes, reject The null hypothesis

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