Question

Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value ofe. P(-eszse) -0.9127 Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places X ?

Answer 1

Variable . bet be standard normal Z and given that P(-cazça) 0.9127 ZNN(o,) to PC-c.$750) 70.9127 to Z we have P(-c<zco) 0.9122 By the propery of gymmetric P(-cezco) 1-2P(Z <-) 0.9122 1-2P(Z <- = 1-2PCZ-C) 0.9122 Cs Scanned with CamScanner

0.9127 I- & P(ZE-C) 1 -0.9127 2P(Z <-c) 2 P(z cc) 0.0873 P(ZE-) 0.04365 standard tables normal From we have 2 PC25-17) - 0.00365 2 from equation C = 1.71 ic 0.9127 P(11.71 szal.70 valke the of C is Therefore C = 1.71 CS Scanned with CamScanner

P(-1.71578177) : 0,9127 Z~N(o,) -1.71 0 +1.71 Z cs Scanned with CamScanner