Question

You kneel beside a fish tank (containing alcohol for unknown reason) and surprisingly found a fish there. You see it by sunlight that reflects off the fish and refracts at the alcohol-air interface as shown in the figure below. What is the angle of refraction (in degrees) if this transparent alcohol has index of refraction given by 1.38?

60° L

A. 43.6

B. 39.9

C. 45.2

D. 41.1

Answer 1

Air (na) 60° 0.44 n = 1:38; no 13 Qiz incident angle, TTTTTTT17 Op = refraction angle. Alcohol now, from snell's law, we get, (no) msindi na sin Dp 0 as, 0i+60°-90 on Di: 90°-60°= 30 now, 1.38 * sin 30°= 1x sindro sinop= 1038 x sin 3 0° Oro, Qroz 143.6° • The angle of refraction is, A. A3.6 0=Y or,